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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

Area of Cut portion \(= 4*π5^2 = 100π\)

Area of UnCut portion \(= π20^2 = 400π\)

Required Ratio \(= 400π/100π = 4/1\)

Answer: Option B
Won't uncut propotion will be 400π-100π = 300π?
Which will leave 3:1 ratio

Posted from my mobile device
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total area of circular sheet ; 400pi
and area of 4 circles * 5 radius each ; (5)^2 *4 * pi ; 100pi
un cut part will be 400pi-100pi ; 300 pi
so ratio of uncut to cut portion ; 300pi/100 pi ; 3:1
OPTION C

Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5
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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

Radius of the main circle = 20 => Area = pi * 400
Radii of the small circles = 5 => Area of the 4 small circles = 4 * pi * 25 = pi * 100
=> Remaining area = 300 * pi

=> Required ratio = 3 : 1

But, let us pause for a moment to think - can we cut out 4 such circles of radius 5 units?
(Note: The part below is NOT related to the question)

Referring to the diagram below: The maximum radius of the small circles:

Attachment:
1.JPG
1.JPG [ 27.63 KiB | Viewed 2903 times ]

From the blue triangle: AB = \(2r * \sqrt{2}\); where r is the radius of the small circles and R is the radius of the big circle
PQ = \(2r * \sqrt{2} + 2r = 2R\)

=> \(r = \frac{R}{(1+\sqrt{2})}\)
= \(\frac{20}{(1+\sqrt{2})}\)
= \(20* (\sqrt{2} - 1)\)
= 20 * 0.4 = 8
Thus, we can always cut out 4 circles of radius 5
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yashikaaggarwal
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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

Area of Cut portion \(= 4*π5^2 = 100π\)

Area of UnCut portion \(= π20^2 = 400π\)

Required Ratio \(= 400π/100π = 4/1\)

Answer: Option B
Won't uncut propotion will be 400π-100π = 300π?
Which will leave 3:1 ratio

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Won't uncut propotion will be 400π-100π = 300π? ---> You are right!
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yashikaaggarwal
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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

Area of Cut portion \(= 4*π5^2 = 100π\)

Area of UnCut portion \(= π20^2 = 400π\)

Required Ratio \(= 400π/100π = 4/1\)

Answer: Option B
Won't uncut propotion will be 400π-100π = 300π?
Which will leave 3:1 ratio

Posted from my mobile device

yashikaaggarwal

Yes you point it out right. Made the correction. :)
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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

The area of the entire paper is 400π cm^2. The area of the 4 circles is 4 x 25π = 100π cm^2. Thus, the ratio of the uncut to cut portion is:

300π : 100π = 3 : 1

Answer: C
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Bunuel
From a circular sheet of paper with a radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

A. 1 : 3
B. 4 : 1
C. 3 : 1
D. 4 : 3
E. 2 :5

\(\frac{π20^2 - 4π5^2}{4π5^2}\)

\(= \frac{400π - 100π}{100π}\)

\(= \frac{300π}{100π}\)

\(= 3 : 1\), Answer must be (C)
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