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[GMAT math practice question]

There is a string \(15\) units in length. By cutting the string, Thomas wants to make two equilateral triangles. If the ratio of the areas of two triangles is \(2:3\), what is the side length of the smaller triangle?

A. \(2\)

B. \(3\)

C. \(5(\sqrt{6}-2) \)

D. \(3(\sqrt{5}-2) \)

E. \(2\sqrt{6}\)

Ratio of Areas = Square of ratio of sides

i.e. Ratio of sides = √2/√3

i.e. Perimeters of two triangles = (Side1+Side2)*3 = (√2x+√3x)*3 = 15

i.e. x = 5/(√2+√3) = 5(√3-√2)

Smaller triangles's side = √2 x = √2*5(√3-√2) = 5(√6-2)

Answer: Option C

Bunuel: This thread to be moved into PS forum

Hi GMATinsight is this a general property for all equilateral triangles? "Ratio of Areas = Square of ratio of sides"
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Kritisood
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[GMAT math practice question]

There is a string \(15\) units in length. By cutting the string, Thomas wants to make two equilateral triangles. If the ratio of the areas of two triangles is \(2:3\), what is the side length of the smaller triangle?

A. \(2\)

B. \(3\)

C. \(5(\sqrt{6}-2) \)

D. \(3(\sqrt{5}-2) \)

E. \(2\sqrt{6}\)

Ratio of Areas = Square of ratio of sides

i.e. Ratio of sides = √2/√3

i.e. Perimeters of two triangles = (Side1+Side2)*3 = (√2x+√3x)*3 = 15

i.e. x = 5/(√2+√3) = 5(√3-√2)

Smaller triangles's side = √2 x = √2*5(√3-√2) = 5(√6-2)

Answer: Option C

Bunuel: This thread to be moved into PS forum

Hi GMATinsight is this a general property for all equilateral triangles? "Ratio of Areas = Square of ratio of sides"

Kritisood

Yes, this property is generalized for any set of similar figures (triangles, quadrilaterals, circles etc.) :)
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i.e. x = 5/(√2+√3) = 5(√3-√2)


Hi,

How did you get the denominator to the numerator here?
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=>

Assume \(x\) and \(y\) are the side lengths of the two triangles where \(x < y.\)

Then we have \(3x + 3y = 15\) or \(x + y = 5.\)

Since the ratio of the areas of those triangles is \(2:3,\) we have \(x^2 : y^2 = 2 : 3\) or \(x : y = √2 : √3.\)

Cross multiplying gives us \(√3x = √2y, y = \frac{(√3x)}{√2}\), and \(y = (\frac{√6}{2})x\) (by multiplying the numerator and denominator by \(√2\)).

Substituting \(y = (\frac{√6}{2})x\) into \(x + y = 5\) gives us:

\(x + y = 5\)

\(x + (\frac{√6}{2})x = 5\)

\((\frac{2}{2})x + (\frac{√6}{2})x = 5\)

\(\frac{√6+2}{2}x = 5.\)

Then \(x = \frac{10}{√6+2}=\frac{10(√6-2)}{2}=5(√6-2).\)

Therefore, C is the answer.
Answer: C
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Hi,
What is the mathematical operation you did in order to change from

i.e. Perimeters of two triangles = (Side1+Side2)*3 = (√2x+√3x)*3 = 15
to
i.e. x = 5/(√2+√3) = 5(√3-√2) ???

Thank you!!
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Hi,
What is the mathematical operation you did in order to change from

i.e. Perimeters of two triangles = (Side1+Side2)*3 = (√2x+√3x)*3 = 15
to
i.e. x = 5/(√2+√3) = 5(√3-√2) ???

Thank you!!

Hi, they took x as common from (√2x+√3x)*3 = 15
x(√2+√3)*3=15
x=5/(√2+√3) = 5(√3-√2)
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