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Updated on: 15 May 2020, 01:44
Originally posted by GMATinsight on 14 May 2020, 00:52.
Last edited by GMATinsight on 15 May 2020, 01:44, edited 1 time in total.
Last edited by GMATinsight on 15 May 2020, 01:44, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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87% (01:10) correct
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All 100 Cards in a stack are numbered with different integers from 1 to 100 inclusive. If Christy chooses one card at random, replaces it in the stack, and chooses another card at random, what is the probability that the product of the two integer values on the chosen cards is odd?
(A) 1/8
(B) 1/4
(C) 1/3
(D) 1/2
(E) 3/4
(A) 1/8
(B) 1/4
(C) 1/3
(D) 1/2
(E) 3/4
Source: https://www.GMATinsight.com
14 May 2020, 04:03
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GMATinsight
Product of the two cards will be ODD if both the cards are odd.
There are 50 odd and 50 even cards
Drawing the first odd card = \(\frac{50}{100}\)
Drawing the second odd card ( replacement is allowed )\(\frac{50}{100}\)
Hence probability = \(\frac{50}{100}\)*\(\frac{50}{100}\) = \(\frac{1}{4}\)
Archit3110
Updated on: 15 May 2020, 01:50
Originally posted by Archit3110 on 14 May 2020, 05:16.
Last edited by Archit3110 on 15 May 2020, 01:50, edited 1 time in total.
Last edited by Archit3110 on 15 May 2020, 01:50, edited 1 time in total.
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from 1 to 100 ; total odd = 50 integers
and to get multiple value of two integers as odd both should be odd
another restriction of question is that card is replaced in stack
so P = 50/100 * 50/100 ; 1/4
OPTION B
and to get multiple value of two integers as odd both should be odd
another restriction of question is that card is replaced in stack
so P = 50/100 * 50/100 ; 1/4
OPTION B
GMATinsight
