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22 May 2020, 10:58
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:36) correct
24%
(02:25)
wrong
based on 435
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For the 64 cubes in the figure above, there is an 8 on each of the faces not shown. If horizontal layer L is rotated 90° so that its front appears on the left side of the figure and then vertical layer R is rotated 90° so that its top appears on the front of the figure, the sum of the numbers on the front of the figure will be
A. 86
B. 93
C. 97
D. 103
E. 106
PS20401
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1.png [ 40.36 KiB | Viewed 8229 times ]
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22 May 2020, 11:17
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First turn, sum of front face= 8x4 + 6x12 = 104
Second turn, sum of front face= 104- (8x1 + 6x3) + (7x4)
= 104-26+28= 106
Ans E
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Second turn, sum of front face= 104- (8x1 + 6x3) + (7x4)
= 104-26+28= 106
Ans E
Posted from my mobile device
Archit3110
Major Poster
22 May 2020, 19:22
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visualise a cube and solve ; 
after the rotation of the cube layer L to 90* horizontal and R to 90* vertical the front face will now be
{6*(9)} + {7*3+8} + {5*3+ 8} = 54+ 29+23 ; 106
OPTION E
after the rotation of the cube layer L to 90* horizontal and R to 90* vertical the front face will now be
{6*(9)} + {7*3+8} + {5*3+ 8} = 54+ 29+23 ; 106
OPTION E
Bunuel
