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Bunuel

A square is inscribed in a big circle and a small circle is inscribed in the square as shown in the figure above. (All of them are concentric and their center is the point O). If the radius of the big circle is √2 cm, what is the perimeter of the small circle?

A. 1
B. 2
C. 3
D. π
E. 2π


Attachment:
1.png

Radius fo Small Circle, r = Side of square = a
Radius fo Big Circle, R = Diagonal of square = a√2

i.e. \(\frac{r}{R} = \frac{a}{a√2}\)

i.e. \(r = (\frac{1}{√2})*√2 = 1\)

\(Circumference = 2πr = 2π\)



Answer: Option E
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Bunuel

A square is inscribed in a big circle and a small circle is inscribed in the square as shown in the figure above. (All of them are concentric and their center is the point O). If the radius of the big circle is √2 cm, what is the perimeter of the small circle?

A. 1
B. 2
C. 3
D. π
E. 2π


Attachment:
1.png

Solution


    • Let us assume that the side of the square is a.
    • Now, Diameter of the big circle = diagonal of the square

      o \(⟹2* \sqrt{2} = a*\sqrt{2} ⟹ a = 2\)
    • Also, side of the square = diameter of the small circle
      o Diameter of the small circle \(= a = 2\)
    • Thus, the circumference of the small circle \(= \pi* diameter = 2*\pi\)
Thus, the correct answer is Option E.
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IMO E.

Diameter of the big circle = Diagonal of square

and Side of square = \sqrt{2} Side of square

Using above we can solve this.
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