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Bunuel
Two machines A and B work at constant rates which are in the ratio of 1:2 respectively. If the two machines work together, they can complete 1/3rd of a job in 3 hours. If machine A starts working on the job and works alone for 18 hours, how many hours would machine B working alone take to complete the remaining work?

A. 3.5
B. 4
C. 4.5
D. 5
E. 5.5
A and B are rates of machines A and B respectively, and they are in 1:2
(Ra+2Ra)*3=1/3
Ra=1/27
in 18 hrs work done by A= 2/3 of the work
remaining work=1/3
for B
2Ra*t=1/3
t=1/6Ra
t=27/6
t=4.5
C:)
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Bunuel
Two machines A and B work at constant rates which are in the ratio of 1:2 respectively. If the two machines work together, they can complete 1/3rd of a job in 3 hours. If machine A starts working on the job and works alone for 18 hours, how many hours would machine B working alone take to complete the remaining work?

A. 3.5
B. 4
C. 4.5
D. 5
E. 5.5

rate of A= 1 and rate of B =2
so in 3 hours work done ; (1+2)*3 = x/3
total work = 27
if A works 18 hours ; left with 27-18; 9 units
which B will do in 9/2 ; 4.5 hours
OPTION C
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I tried to solve this question my own way and really couldn't get the answer, can someone help?

If worker B's rate is 1/x, the slower workers rate will be 1/2x. Now, we know it takes them 3 hours to complete 1/3rd of the task, so 9 hours for the full task. 1/x + 1/2x = 1/9

Based on this, I can solve for the rate of the 2 workers, and get B as 2/27 and A as 2/54.

If A works for 18 hours, it does (2/54)*18 amount of work, which is 2/3rd of the work. Remaining work is (2/3)*(1/9). This is where I'm getting 2/27, so it would take machine B 1 hour to do the remaining work.

Where am I going wrong? Thanks. cc Bunuel
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Starscreen60
I tried to solve this question my own way and really couldn't get the answer, can someone help?

If worker B's rate is 1/x, the slower workers rate will be 1/2x. Now, we know it takes them 3 hours to complete 1/3rd of the task, so 9 hours for the full task. 1/x + 1/2x = 1/9

Based on this, I can solve for the rate of the 2 workers, and get B as 2/27 and A as 2/54.

If A works for 18 hours, it does (2/54)*18 amount of work, which is 2/3rd of the work. Remaining work is (2/3)*(1/9). This is where I'm getting 2/27, so it would take machine B 1 hour to do the remaining work.

Where am I going wrong? Thanks. cc Bunuel

You did the mistake in the last line -
"If A works for 18 hours, it does (2/54)*18 amount of work, which is 2/3rd of the work. Remaining work is (2/3)*(1/9). This is where I'm getting 2/27, so it would take machine B 1 hour to do the remaining work."

A completed 2/3rd of the work. Correct
Work remaining for B = 1/3rd. Rate of B = 2/27
So time = \(\frac{Work }{ Rate }=\frac{1}{3} * \frac{27}{2 } = \frac{9}{2} = 4.5 \)
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