If 0.2t = 2.2 - 0.6s and 0.5s = 0.2t + 1.1, then s=

Question

(A) 1
(B) 3
(C) 10
(D) 11
(E) 30

GMATinsight · Answer

0.2t = 2.2 - 0.6s
i.e. 2t + 6s = 22
i.e. t + 3s = 11
i.e. 2t + 6s = 22-----(1)

0.5s = 0.2t + 1.1
i.e. 5s - 2t = 11-----(2)

Adding two equations

11s = 33
s = 3
and t = 2

Answer: Option B

dimri10 · Answer

2.2-0.6s=0.5s-1.1
3.3=1.1s
S=3

Posted from my mobile device

bM22 · Answer

Eq 1. = 0.2t + 0.6s = 2.2
Eq 2. = 0.2t - 0.5s = -1.1

Equating the 2 eqns we get: 1.1s = 3.3
=> s = 3.
 
Answer B.

yashikaaggarwal · Answer

0.2t = 2.2 - 0.6s
2t/10 = 22/10 - 6s/10
2t = 22 - 6s
t = 22-6s/2 => 11-3s -------(1)

0.5s = 0.2t + 1.1
5s/10 = 2t/10 + 11/10
5s = 2t + 11
5s - 11 = 2t
t = (5s-11)/2 ----------(2)

(5s-11)/2 = 11-3s 
5s - 11 = 22-6s
11s = 33
S = 3

Answer is B

Posted from my mobile device

Babineaux · Answer

Given,

0.2t = 2.2 - 0.6s;

Putting the value of 0.2t,

0.5s = 2.2 - 0.6s + 1.1;

or, 1.1s = 3.3;

or, s = 3;

IMO ans is B.

BlueRocketAsh · Answer

0.5s=0.2t+1.1 
 0.5s=2.2-0.6s+1.1 
 0.5s+0.6s=2.2+1.1 
 1.1s=3.3 
 s=3

Prep Toolkit