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07 Jul 2020, 03:01
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Difficulty:
95%
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Question Stats:
38% (02:24) correct
62%
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wrong
based on 55
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Two students played a game of catch on the roof of the chemistry building, which was 1,750 feet high. Unfortunately, after a bad throw, the ball fell to the ground and bounced several times. With each consecutive bounce, the ball reaches a height that is the same fraction of the height it reached on its previous bounce. If the ball reaches a height of 897 feet after its fifth bounce, what is this fraction?
A. 1/8
B. 1/6
C. 3/4
D. 5/6
E. 7/8
A. 1/8
B. 1/6
C. 3/4
D. 5/6
E. 7/8
yashikaaggarwal
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07 Jul 2020, 03:24
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Let the fraction be X
1750x^5 = 897
X^5 = 897/1750
X^5 = 3*13*23/2*5*5*5*7
X^5 = 0.51257
Taking 5th root
X = 0.1025
Value of options in decimal =
A. 1/8 = 0.125
B. 1/6 = 0.166
C. 3/4 = 0.750
D. 5/6 = 0.833
E. 7/8 = 0.875 (Closest Value)
IMO E
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1750x^5 = 897
X^5 = 897/1750
X^5 = 3*13*23/2*5*5*5*7
X^5 = 0.51257
Taking 5th root
X = 0.1025
Value of options in decimal =
A. 1/8 = 0.125
B. 1/6 = 0.166
C. 3/4 = 0.750
D. 5/6 = 0.833
E. 7/8 = 0.875 (Closest Value)
IMO E
Posted from my mobile device
Mo2men
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07 Jul 2020, 04:34
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