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Can be solved using double matrix


6FT <6FT TOTAL
GREEN 220 80 300

BLUE 20 200

TOTAL 400 100 500


First fill in numbers which are given, total green eyed 300, blue eyed 200, 6ft models: 400
Now we fill 100 , to make total 500. now 100 models less than 6ft.

10% of 200 is 20, so blue eyed < 6 ft 20
less than 6ft = 80,,

Required: 300-80 = 220, Green eyed+ 6ft

IMO E
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Bunuel
At a local modeling agency with 500 models, 300 have green eyes and the rest have blue eyes. If 400 of the models are over six feet tall and ten percent of the blue eyed models are less than six feet tall, how many of the green eyed models are over six feet tall?

A. 20
B. 80
C. 100
D. 180
E. 220

Answer: Option E

Please check the step by step Video solution using DOUBLE MATRIX METHOD...

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At a local modeling agency with 500 models, 300 have green eyes and the rest have blue eyes. If 400 of the models are over six feet tall and ten percent of the blue eyed models are less than six feet tall, how many of the green eyed models are over six feet tall?

ANS: E (220)

Total: 500
Green eyes: 300
Blue eyes: 200

Models over 6 feet: 400
Models less than 6 feet: 100

Blue eyes models less than 6 feet: 0.10 *200 = 20
Green eyes models less than 6 feet: 80 (as total less than 6 feet tall models are 100)

Green eyes models over 6 feet: 300-80 = 220

Hope it helps..
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Bunuel
At a local modeling agency with 500 models, 300 have green eyes and the rest have blue eyes. If 400 of the models are over six feet tall and ten percent of the blue eyed models are less than six feet tall, how many of the green eyed models are over six feet tall?

A. 20
B. 80
C. 100
D. 180
E. 220

90% of the blue-eyed models are over 6 feet tall = 200* .9 = 180
Rest 6 feet tall models = 220, who are green-eyed
E is the answer.
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