Bunuel
The Q members of the senior class agree to split the cleanup costs equally for their graduation dance, which will be P dollars. If R students fail to graduate and do not pay their share, but the cleanup costs remain the same, how many additional dollars will each of the remaining students have to contribute to pay the cleanup costs?
A. P/(Q - R)
B. (P/Q)(R - Q)
C. PQ/(Q - R)
D. PR/(Q(Q - R))
E. PQR/(Q(Q - R) )
I.
Quickest - logical We are looking for ' additional dollars per remaining student', so we should have dollars, here P, in numerator, and number of students in denominator in simplified form. Remember each of Q, R, or Q-R will give number of students.
Only A and D are possible....
A clearly gives us the total amount that each would pay, but we are looking for additional dollars..D is the answer
II.
Take numbersLet P = 20, Q=10 and R=8..
So Initial they were to pay = \(\frac{20}{10}=2\), but now \(\frac{20}{(10-8)}\)=10...addl dollars = 10-2=8
A. \(\frac{P}{(Q - R)}=\frac{20}{2}=10\)
B. \((\frac{P}{Q})(R - Q)\)..R-Q<0, so discard
C. \(\frac{PQ}{(Q - R)}=\frac{10*20}{8}=25\)...NO
D. \(\frac{PR}{(Q(Q - R))}=\frac{20*8}{10*(10-8)}=8\)...YES
E. \(\frac{PQR}{(Q(Q - R) )}=\frac{10*20*8}{10*2}=80\)...NO
III.
Proper methodInitial each of Q were paying = \(\frac{P}{Q}\)...(i)
After R left, each of Q-R were to pay = \(\frac{P}{Q-R}\)...(ii)
Additional paid per person = ii-i
\(\frac{P}{Q-R}-\frac{P}{Q}=\frac{P(Q-(Q-R))}{Q(Q-R)}=\frac{PR}{Q(Q-R)}\).
D