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If you subtract consecutive terms in this sequence, i.e. if you compute S_n - S_(n+1), you just get 5n - 5(n + 1) = -5 (I'm omitting the "+94" each time since it will cancel). In the calculation we're asked to do in this question, we're just subtracting three pairs of consecutive terms, and adding what we get, so the answer is -15.
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If Sn = 5n + 94 and K = (S80 + S82 + S84) − (S81 + S83 + S85), what is the value of K ?

(A) −282
(B) −84
(C) −30
(D) −15
(E) −3

Solution:

S80 = 5(80) + 94

S81 = 5(81) + 94

S82 = 5(82) + 94

S83 = 5(83) + 94

S84 = 5(84) + 94

S85 = 5(85) + 94

We see that the 3 terms of 94 from S80, S82 and S84 will cancel the same three 3 terms in S81, S83 and S85 when you subtract the two sums. Therefore, we have:

(S80 + S82 + S84) − (S81 + S83 + S85)

= [5(80)+ 5(82) + 5(84)] - [5(81)+ 5(83) + 5(85)]

= 5(80 + 82 + 84 - 81 - 83 - 85)

= 5(-1 - 1 - 1)

= -15

Answer: D
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If Sn = 5n + 94 and K = (S80 + S82 + S84) − (S81 + S83 + S85), what is the value of K ?

First of all, let's consider only the units as the tens will cancel out with the sustraction
Then, let's dump the +94 because it will cancel out too.

We are left with 5n and (S0+S2+S4)-(S1+S3+S5) = (0+10+20)-(5+15+25) = 30-45 = -15

With this method, it will only take you seconds to solve the question

Answer D)
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