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A diameter of a figure is defined as a maximum distance AB where points A, B belong to the figure. For example, the diameter of the parallelogram is the parallelogram's longer diagonal. If the diameter of the cube is 3, what is the area of the surface of the cube?

Maximum distance of a cube with side 'a' = \(\sqrt{a^2 + a^2+ a^2}\) = \(\sqrt{3}a\)

Given \(\sqrt{3}a\)=3; a=\(\sqrt{3}\)

area of the surface of the cube= 6 * \(a^2\)= 6 * 3=18


A. 3
B. 6
C. 63√63
D. 18
E. 123√
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When are these new GMATCLUB Test Questions going to be added to the CATs ?
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