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Bunuel
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bond001

The question says he travel every day reduces by 20% not to 20%

So shouldn't new speed be \(5(1-\frac{20}{100})\)=\(5(\frac{4}{5})\) instead of \(5(\frac{1}{5})\)

and thus whole expression would become \(5 + 5(\frac{4}{5} +\frac{ 4}{5}^2 + \frac{4}{5}^3 + ..)\) ?
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the answer should be 25 +1 days right?
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no it is supposed to be 25 days. but I am seriously confused. the answer does not seem to be right.
riyagupta2455
the answer should be 25 +1 days right?
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A man takes 20 days to reach the point B under normal circumstances. But, due to the increasingly hostile weather conditions the distance he travel every day reduces by 20%, starting from day 2.

In how many days would the man reach the point B, taking into consideration weather conditions?

Let the distance travelled by the man be 1 unit / day

Distance travelled in 20 days under normal circumstances = 20 units

Under hostile weather conditions: -
Distance travelled in Day 1 = 1 unit
Distance travelled in Day 2 = .8 units
Distance travelled in Day 3 = .8^2 units

Distance travelled in Day n = (.8)^{n-1} units

Total distance travelled = 1 + .8 + .8^2 + .... + (.8)^{n-1} = 20

(1- .8^n)/(1-.8) = (1-.8^n)/.2 = 20
1- .8^n = 4
.8^n = 1 - 4 = - 3

Not feasible; He cannot reach the destination

IMO E
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