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Bunuel
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bond001

The question says he travel every day reduces by 20% not to 20%

So shouldn't new speed be \(5(1-\frac{20}{100})\)=\(5(\frac{4}{5})\) instead of \(5(\frac{1}{5})\)

and thus whole expression would become \(5 + 5(\frac{4}{5} +\frac{ 4}{5}^2 + \frac{4}{5}^3 + ..)\) ?
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