Three snipers shoot a certain target. Their probabilities of hitting

Question

Three snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability that all three missed the target?

A. 0.015
B. 0.185
C. 0.485
D. 0.515
E. 0.985

The snipers shoot a certain target. Their probabilities of hitting the target are 0.9, 0.7, and 0.5 respectively. The snipers make one salvo. What is the probability:

1. that exactly one sniper missed?
2. that exactly one sniper hit?
3. that exactly two snipers missed?
4. that exactly two snipers hit?

CrackverbalGMAT · Answer

If the probability of an event happening is P(A), then the probability that the even wont happen = 1 - P(A)

Probability that the first sniper misses = 1 - 0.9 = 0.1.

Probability that the second sniper misses = 1 - 0.7 = 0.3.

Probability that the third sniper misses = 1 - 0.5 = 0.5.

Probability that all 3 miss their target = 0.1 * 0.3 * 0.5 = 0.015

Option A

Arun Kumar

AnirudhaS · Answer

1 salvo here means the snipers take 1 shot each
All miss the target = (1-0.9) * (1-0.7) * (1-0.5) = 0.015

Answer:  A

rocky620 · Answer

Probabilities of hitting the target are 0.9, 0.7, and 0.5
Probabilities of missing the target are 0.1, 0.3, and 0.5

Probability that all three miss the targets = 0.1 * 0.3 * 0.5 = .015

Option A

anjanita · Answer

I think the answer is A. Here is my two cents

Let 3 shoots A, B and C.

P(A)=0.9,P(A′)=1−0.9=0.1
P(B)=0.7,P(B′)=1−0.7=0.3
P(C)=0.5,P(C′)=1−0.5=0.5
Probability of all three snipers missed their target = P(A′)×P(B′)×P(C′)
=0.1*0.3*0.5
=0.015

Three snipers shoot a certain target. Their probabilities of hitting

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Three snipers shoot a certain target. Their probabilities of hitting

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