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26 Feb 2021, 05:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
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Question Stats:
77% (00:42) correct
23%
(00:54)
wrong
based on 160
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Two dice, each numbered 1 to 6, are tossed. What is the probability that neither shows a "4" ?
A. 1/36
B. 4/36
C. 11/36
D. 25/36
E. 35/36
A. 1/36
B. 4/36
C. 11/36
D. 25/36
E. 35/36
wishmasterdj
Joined: 04 May 2016
Last visit: 25 Oct 2021
Posts: 91
Given Kudos: 10
Location: India
Schools: ISB '18 (A)
GMAT 1: 700 Q48 V37
GPA: 3.2
26 Feb 2021, 21:25
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remove 4 from each of the possible cases:
5/6 * 5/6 = 25/36
Hence D
5/6 * 5/6 = 25/36
Hence D
26 Feb 2021, 21:34
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Bunuel
Probability of first die to not show '4' \(= \frac{5}{6}\)
Probability of Second die to not show '4' \(= \frac{5}{6}\)
Probability that neither shows a "4" \(= \frac{5}{6}*\frac{5}{6} = \frac{25}{36}\)
Answer: Option D
