Three students P, Q, R are standing in a line. There are 5 students st

Question

Three students P, Q, R are standing in a line. There are 5 students standing in the line between P and Q and 8 students standing in the line between Q and R. If there are 3 students standing in the line before R and 21 students standing in the line behind P. Then what is the minimum number of the student standing in the line?

A. 41
B. 40
C. 28
D. 27
E. None of these

A. 41
B. 40
C. 28
D. 27
E. None of these

HoneyLemon · Answer

Min Students in Line

...R..P.....Q ............... = Total  28

Max student in Line

...R.... ....Q .....P ... ... ... ... ... ... ... = Total = 40

AndrewN · Answer

Yes, as long as you remember to count R, P, and Q themselves as individuals in the line, you should get 28. Although  HoneyLemon  indicated such individuals using dots in the above post, I have a hard time counting them beyond about five. So, for the more numerically oriented (i.e. dot-challenged) reader:

R   P   Q

Check the facts. 
  Are 5 students  between  P and Q?  Yes .   Are 8 students  between  Q and R?  Yes . (Do not forget to count P.)   Are 3 students  ahead  of R?  Yes .   Are 21 students  behind  P?  Yes . (Do not forget to count Q.)

Since the above lineup conforms to all the given information, we know we have our answer: 3 + 1 + 2 + 1 + 5 + 1 + 15 = 28, so   the answer is (C)  . Good luck with your studies, everyone.

- Andrew

Kinshook · Answer

Given: 
Three students P, Q, R are standing in a line. 
There are 5 students standing in the line between P and Q and 8 students standing in the line between Q and R. 
There are 3 students standing in the line before R and 21 students standing in the line behind P.

Asked: What is the minimum number of the student standing in the line?

P _ _ _ _ _ Q or Q _ _ _ _ _ P
R _ _ _ _ _ _ _ _ Q or Q _ _ _ _ _ _ _ _ R
_ _ _ R _ _ P _ _ _ _ _ Q _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

Minimum number of students standing in the line = 3 + 1 + 2 + 1 + 21 = 28

IMO C

billionaire999 · Answer

3 before R, 8 between r and q, 5 between p and q, 21 behind p

so if we place R after 3people, two more people the P, the there will be 5 more people and q. So after p we have 21 people (-q, - 5 between p and q)

3+r+2+P+5+Q+ 15= 28

Hence ANS= C+28

Fdambro294 · Answer

...........13th spot = Q......... .....7th Spot = P......... ......4th Spot = R.........

Minimum total people in line =

15 + Q + 5 + P + 2 + R + 3

Where Q, P, and R each take up 1 spot

28

Posted from my mobile device

Regor60 · Answer

To minimize the number of students maximize the overlap of the 5 students between P&Q and the 8 students between Q&R.

So, there are only two possible orders and with the initial information:

Q5P2R and R2P5Q

Having been told that there are 3 people before R, only the second order is possible, which means the order now becomes:

3R2P5Q

Finally, being told that there are 21 people before P, the number of people before Q becomes:

21-5-1(Q) = 15

So the final order is:

3R2P5Q15

Adding these = 28

Posted from my mobile device

Three students P, Q, R are standing in a line. There are 5 students st

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Three students P, Q, R are standing in a line. There are 5 students st

Prep Toolkit

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