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A container contains 210 L of wine. 70 L is taken out of the container 05 Mar 2021, 05:00
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71% (02:30) correct 29% (02:51) wrong based on 356 sessions

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A container contains 210 L of wine. 70 L is taken out of the container every day and an equal quantity of water is put into it. What is the quantity of the wine that remains in the container at the end of the third day ?

(A) 62 2/9 L
(B) 60 2/9 L
(C) 56 1/2 L
(D) 51 1/9 L
(E) 50 1/9 L
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A
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A container contains 210 L of wine. 70 L is taken out of the container 28 Mar 2021, 09:16
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Bunuel
A container contains 210 L of wine. 70 L is taken out of the container every day and an equal quantity of water is put into it. What is the quantity of the wine that remains in the container at the end of the third day ?

(A) 62 2/9 L
(B) 60 2/9 L
(C) 56 1/2 L
(D) 51 1/9 L
(E) 50 1/9 L
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We take out \(\frac{70}{210} = \frac{1}{3}\) of the liquid each day, which means we are taking out one-third of wine and water every time before refilling. Therefore \(1 - \frac{1}{3} = \frac{2}{3}\) of wine is leftover each time we do this.

Repeat three times since we're asking for end of 3rd day. \(210 * (\frac{2}{3})^3 = 70*\frac{8}{9} = \frac{560}{9} = 60 + \frac{20}{9} = 62\frac{2}{9}\).

Ans: A
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A container contains 210 L of wine. 70 L is taken out of the container 14 Mar 2021, 04:10
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I believe it's a little unclear the fact that he doesn't subtract 70 L each day but actually 1/3 of the wine left.

Said that, we can solve it in this way:

210-70= 140
140 - (140/3)= 280/3
(280/3) - (280/9)= 560/9, simplify and you find 62 + 1/9 ----> A
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A container contains 210 L of wine. 70 L is taken out of the container 22 Mar 2021, 04:23
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please provide easier way to deal with this problem
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A container contains 210 L of wine. 70 L is taken out of the container 28 Mar 2021, 02:18
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nityakaul02
please provide easier way to deal with this problem
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Hello Nitya, nityakaul02

Day 0 = 210 liters of wine

Day 1 end = 210 -70(of mixture is removed) + 70 liters of water added

DAY 1 END 140L wine , 70L Water

Day 2 = 70L out of 210L is removed. 70/210 = 1/3

so 140/3L wine removed, 70/3L water removed, 70L liters water added

DAY 2 END wine left = approx 93 L wine left


DAY 3 again 70 out of 210 liters is removed

i.e. 1/3

93/3 L of wine removed, i.e. 31 liters approx of wine was removed

DAY 3 end

62L of wine approx remaining.

ANSWER A
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A container contains 210 L of wine. 70 L is taken out of the container 24 Nov 2022, 23:18
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can we do this with C2/C1=(V1/V2)^n ??
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A container contains 210 L of wine. 70 L is taken out of the container 25 Sep 2024, 18:24
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So,

Quote:
Final conc of wine= Initial conc.* Initial Volume of sol. / Final Volume of sol
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The volume of the mixture after removing 70L of wine: 140
The volume of the mixture after adding 70L of water: 210
so, 100% (conc. of wine) * 140/210

We do this 3 times so the final concentration of wine= 100%* 2/3 * 2/3 * 2/3

And we know that
Quote:
Amount of Wine= Conc of wine* Volume of mixture
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Amount of wine= 210* 2/3* 2/3* 2/3
Amount of wine= 62 2/9
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A container contains 210 L of wine. 70 L is taken out of the container 15 Oct 2024, 06:35
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Final= Initial(1- amount replaced/total amount)^number of times replaced

by this formula;
final amount= 210(1-70/210)^3
Answer= 62 2/9 (A)
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A container contains 210 L of wine. 70 L is taken out of the container 20 Nov 2025, 22:56
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