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Bunuel
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With the same equation i.e 11>= 2w, I have the values 1 to 5 that satisfy it, then why B and not C?
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w<=(11+w)/3<=3w

3w<=11+w<=9w

at w=1, w=0,w=-1 doesn't satisfy
at w=2 -->6<=13<=18 (satisfies)
similarly satisfies for w=3,4,5
Total satisfied cases four, hence option (B) - FOUR
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The average of the 3 numbers is going to be:

(3+8+W)/3 >\= W

Multiply both sides by 3:

(3+8+W) >/= 3W

Simplify:

5.5 >/= W

Same with second inequality:

(3+8+W)/3 </= 3W

11 </= 8W

11/8 </= 8W

11/8 = 1.375

Count the integers between 1.375 and 5.5: 2, 3, 4, 5.

B is the answer.

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Solutions are 2, 3, 4,5
So, four ans B

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