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28 Apr 2021, 02:15
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
72% (02:40) correct
28%
(02:57)
wrong
based on 201
sessions
History
Date
Time
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Not Attempted Yet
A motorist covers a distance of 39 km in 45 min by moving at a speed of x km/h for the first 15 min, then moving at double the speed for the next 20 min and then again moving at his original speed for the rest of the journey. Then, x is equal to:
(A) 31.2
(B) 36
(C) 40
(D) 52
(E) 53
(A) 31.2
(B) 36
(C) 40
(D) 52
(E) 53
28 Apr 2021, 02:32
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Bunuel
Quote:
i.e. Speed \(= \frac{39}{45}*60 = 52\) kmph
x km/h for the first 15 min
i.e. Distance \(= x*\frac{15}{60} = \frac{x}{4}\) km
2x km/h for the first 20 min
i.e. Distance \(= 2x*\frac{20}{60} = \frac{2x}{3}\) km
x km/h for the first 45-(15+20)= 10 min
i.e. Distance \(= x*\frac{10}{60} = \frac{x}{6}\) km
Total Distance = \(39 = \)\(\frac{x}{4}\)+\(\frac{2x}{3}\)+\(\frac{x}{6}\)
i.e. \(\frac{13x}{12} = 39\)
x = 36 kmph
Answer: Option B
28 Apr 2021, 02:36
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Answer is B.
Let initial speed be x km/hr
x.(15/60) + 2x.(20/60) + x.(10/60) = 39
x/4 + 2x/3 + x/6 = 39
(3x+8x+2x)/12 = 39
13x = 39.12
x = 12.3
x=36
Let initial speed be x km/hr
x.(15/60) + 2x.(20/60) + x.(10/60) = 39
x/4 + 2x/3 + x/6 = 39
(3x+8x+2x)/12 = 39
13x = 39.12
x = 12.3
x=36
