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Expanding on a longer method:

1 = (WW) + (WB) + (BW) + (BB)

B is breaks; W is works

We have to find (WW) + (WB) + (BW) which is 9/25 + 6/25 + 6/25 = 21/25
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Bunuel
A canoe has two oars, left and right. Each oar either works or breaks. The failure or non-failure of each oar is independent of the failure or non-failure of the other. You can still row the canoe with one oar. The probability that the left oar works is 3/5. The probability that the right oar works is also 3/5. What is the probability that you can still row the canoe?

A. 9/25
B. 10/25
C. 6/10
D. 2/3
E. 21/25

Canoe does not work if both oars do not work
Probability that canoe will not work = \(\frac{2}{5}*\frac{2}{5} \)= \(\frac{4}{25}\)
Probability that canoe works = 1- probability that canoe does not work = 1-\(\frac{ 4}{25}\) = \(\frac{21}{25}\)

E is the answer
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