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19 May 2021, 20:00
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
66% (01:41) correct
34%
(01:48)
wrong
based on 133
sessions
History
Date
Time
Result
Not Attempted Yet
A set of pictures of butterflies contains 10 pictures. Jim bought 3 of the pictures. If 2 pictures are to be picked out from the 10 pictures, what is the probability that both pictures are not those that were already bought by Jim?
A. 14/15
B. 3/5
C. 6/13
D. 7/15
E. 7/10
A. 14/15
B. 3/5
C. 6/13
D. 7/15
E. 7/10
19 May 2021, 20:15
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Bookmarks
The numbers of way to pick 2 pic from 10 pic is C(10,2) = 45
The number of way to pick 2 pic from remain 7 pic not bought by Jim is C(7,2) = 21
=> The prob = 21/45 = 7/15
Hence choice D
The number of way to pick 2 pic from remain 7 pic not bought by Jim is C(7,2) = 21
=> The prob = 21/45 = 7/15
Hence choice D
RamseyGooner
Current Student
Joined: 29 Feb 2020
Last visit: 03 Oct 2022
Posts: 54
Own Kudos:
Given Kudos: 56
Location: India
Schools: Said '23 (A) Judge '23 (WA) Bocconi (A$$) ESSEC (A)
GMAT 1: 720 Q49 V40
GPA: 3.5
Schools: Said '23 (A) Judge '23 (WA) Bocconi (A$$) ESSEC (A)
GMAT 1: 720 Q49 V40
Posts: 54
Kudos:
54
09 Jun 2021, 12:58
Kudos
Bookmarks
P(Not Jims Pictures) = Favourable Outcomes (Not Jims pictures)/ total Outcomes (All pictures) = 7C2/10C2 = 7/15
Hope this helps!
Hope this helps!
