Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
Updated on: 02 Jun 2021, 23:34
Originally posted by ibakhronov on 02 Jun 2021, 23:01.
Last edited by chetan2u on 02 Jun 2021, 23:34, edited 1 time in total.
Last edited by chetan2u on 02 Jun 2021, 23:34, edited 1 time in total.
Edited
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:48) correct
29%
(02:09)
wrong
based on 21
sessions
History
Date
Time
Result
Not Attempted Yet
Sides of a polygon are in arithmetic progression that has a difference equal to 4. The perimeter of the polygon is 75 and the largest side is equal to 23. Find the number of sides of the polygon.
A. 5
B. 6
C. 7
D. 8
E. 9
A. 5
B. 6
C. 7
D. 8
E. 9
sherxon
Joined: 28 May 2021
Last visit: 09 Nov 2025
Posts: 130
Own Kudos:
Given Kudos: 30
Location: Uzbekistan
Concentration: Strategy, General Management
Schools: Carlson (A$$$) Kenan-Flagler '25 (A$$$$) Goizueta '25 (A$$$) Olin '25 (A$$$$) Fuqua '25 (M$$$$) Marshall '25 (A$$$$)
GMAT 1: 740 Q50 V40
GMAT 2: 770 Q50 V46 (Online)
GPA: 4
Products:
Schools: Carlson (A$$$) Kenan-Flagler '25 (A$$$$) Goizueta '25 (A$$$) Olin '25 (A$$$$) Fuqua '25 (M$$$$) Marshall '25 (A$$$$)
GMAT 2: 770 Q50 V46 (Online)
Posts: 130
Kudos:
238
02 Jun 2021, 23:20
Kudos
Bookmarks
The largest side is 23 units long, leaving 52 units for other sides
The number of sides cannot be 3 as 52 cannot be divided into two parts that are smaller than 23.
let's reverse the progression, making the difference -4 and the first term 23.
So the sum of terms:
\(\frac{2*23 + (n-1)*(-4)}{2}*n = 75\)
Solving for n gives us n = 7.5 or 5
As number of sides has to be an integer
the answer is 5
A
The number of sides cannot be 3 as 52 cannot be divided into two parts that are smaller than 23.
let's reverse the progression, making the difference -4 and the first term 23.
So the sum of terms:
\(\frac{2*23 + (n-1)*(-4)}{2}*n = 75\)
Solving for n gives us n = 7.5 or 5
As number of sides has to be an integer
the answer is 5
A
02 Jun 2021, 23:33
Kudos
Bookmarks
ibakhronov
The sum, 75, is very less, and, therefore, can be calculated for sides easily.
numbers with difference 4 = 23, 19, 15, 11, 7, 3
23+19=42
42+15=67
57+11=68
68+7=75
SO 5 sides: 7, 11, 15, 19, 23
A
