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11 Jun 2021, 07:24
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
66% (03:12) correct
34%
(03:09)
wrong
based on 199
sessions
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Every secretary at a certain company types 80 words per minute. One secretary began typing a 134,400 word manuscript at 9:00 a.m. on a certain day, and at the end of each hour was joined by one additional secretary. At what time was the typing of the manuscript completed?
A) 2:00 p.m.
B) 3:00 p.m.
C) 4:00 p.m.
D) 5:00 p.m.
E) 6:00 p.m.
A) 2:00 p.m.
B) 3:00 p.m.
C) 4:00 p.m.
D) 5:00 p.m.
E) 6:00 p.m.
Updated on: 18 Sep 2025, 20:28
Originally posted by BrushMyQuant on 12 Jun 2021, 08:59.
Last edited by BrushMyQuant on 18 Sep 2025, 20:28, edited 1 time in total.
Last edited by BrushMyQuant on 18 Sep 2025, 20:28, edited 1 time in total.
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Every secretary at a certain company types 80 words per minute
=> In one hour each secretary will type 80*60 = 4800 words
One secretary began typing a 134,400 word manuscript at 9:00 a.m. on a certain day, and at the end of each hour was joined by one additional secretary
Total words to be types is 134400 and every hour the rate increases by 4800 words/hour
9-10am -> 4800 words
10-11am -> 4800*2 words
11am-12pm -> 4800 * 3 words
and so on...
If we take 4800 common we get
Total words typed = 4800(1+2+3+...) = 134400
=> (1+2+3+...) = \(\frac{134400}{4800}\) = 28
1+2+3...+n = 28
=> \(\frac{n*(n+1)}{2}\) = 28
=> n*(n+1) = 28*2 = 56 = 7*8
=> n = 7
1st hour gets over at 10am, second gets over at 11am => 7th will get over at 10+7-1 = 10+6 = 16
=> 4 pm
So, Answer will be C
Hope it helps!
Watch the following video to MASTER Work Rate Problems
=> In one hour each secretary will type 80*60 = 4800 words
One secretary began typing a 134,400 word manuscript at 9:00 a.m. on a certain day, and at the end of each hour was joined by one additional secretary
Total words to be types is 134400 and every hour the rate increases by 4800 words/hour
9-10am -> 4800 words
10-11am -> 4800*2 words
11am-12pm -> 4800 * 3 words
and so on...
If we take 4800 common we get
Total words typed = 4800(1+2+3+...) = 134400
=> (1+2+3+...) = \(\frac{134400}{4800}\) = 28
1+2+3...+n = 28
=> \(\frac{n*(n+1)}{2}\) = 28
=> n*(n+1) = 28*2 = 56 = 7*8
=> n = 7
1st hour gets over at 10am, second gets over at 11am => 7th will get over at 10+7-1 = 10+6 = 16
=> 4 pm
So, Answer will be C
Hope it helps!
Watch the following video to MASTER Work Rate Problems
General Discussion
12 Jun 2021, 09:00
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We are given the rate of every secretory is same (i.e 80 wpm)
Every hour a new typist joins;
At 1st hour there will be ‘1’
2nd hour there will be ‘1+1’
And so on..
Series will be n, n+1, n+2, n+3 ...
Now we are given total words to be typed 134400.
Rate of single typist (in hour) = 60*80 wph = 4800 wph
Dividing 134400 by 4800, we get 28
Every time a typist will be added, additional 4800 words will be typed per hour.
We know the series, so we can find number of typist by subtracting consecutive numbers..
28-1 = 27; 27-2 = 25; 25-3 = 22; 22-4 = 18; 18-5 = 13; 13-6 = 7; 7-7 = 0
7th term will make zero, hence we are required to add 7 additional typist every hour
Time will be 9:00 am + 7 hours = 4:00 pm
Hence, answer is C
Posted from my mobile device
Every hour a new typist joins;
At 1st hour there will be ‘1’
2nd hour there will be ‘1+1’
And so on..
Series will be n, n+1, n+2, n+3 ...
Now we are given total words to be typed 134400.
Rate of single typist (in hour) = 60*80 wph = 4800 wph
Dividing 134400 by 4800, we get 28
Every time a typist will be added, additional 4800 words will be typed per hour.
We know the series, so we can find number of typist by subtracting consecutive numbers..
28-1 = 27; 27-2 = 25; 25-3 = 22; 22-4 = 18; 18-5 = 13; 13-6 = 7; 7-7 = 0
7th term will make zero, hence we are required to add 7 additional typist every hour
Time will be 9:00 am + 7 hours = 4:00 pm
Hence, answer is C
Posted from my mobile device
