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07 Jul 2021, 08:15
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If a set of data has a mean of 4.2 and a standard deviation of 7.1, what is the range of values that lie within 2 standard deviations of the mean?
(A) -2.9 to 11.3
(B) -2.9 to 12.6
(C) -10 to 12.6
(D) -10 to 18.4
(E) 4.2 to 18.4
(A) -2.9 to 11.3
(B) -2.9 to 12.6
(C) -10 to 12.6
(D) -10 to 18.4
(E) 4.2 to 18.4
07 Jul 2021, 12:22
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Bunuel
Standard deviation = 7.1
2 standard deviations = 2 * 7.1 = 14.2
Least value = 4.2 - 14.2 = -10
Greatest value = 4.2 + 14.2 = 18.4
Range = -10 to 18.4,(D) IMO!
mohammadfaraaz123
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07 Jul 2021, 23:56
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We need to calculate the distance from the mean on both sides of the number line.
Mean = 4.2
Standard Deviation = 7.1
Range is going to be all the numbers between smallest and largest value.
Hence,
Lowest possible value = 4.2 - (7.1 + 7.1) = 4.2 -14.2 = -10
Largest possible value = 4.2 + (7.1 + 7.1) = 4.2 + 14.2 = 18.4
Range = -10......Mean......18.4
Answer option D imo
Mean = 4.2
Standard Deviation = 7.1
Range is going to be all the numbers between smallest and largest value.
Hence,
Lowest possible value = 4.2 - (7.1 + 7.1) = 4.2 -14.2 = -10
Largest possible value = 4.2 + (7.1 + 7.1) = 4.2 + 14.2 = 18.4
Range = -10......Mean......18.4
Answer option D imo
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21 Jul 2026, 04:10
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Bunuel can you please explain this concept and question?
