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Three positive integers a, b, and c.

Option E: a + b + c will be greater than the median.

Answer E
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Theory: In case of odd number of numbers in the set: Median is the middle number (after the numbers are arranged in increasing/ decreasing order )

So, median of the set a,b,c can be any of the numbers a, b or c (depending on which one falls in the middle after we arrange them in increasing/ decreasing order)

Let's try to prove each and every options choice! (Tip: Skim through the answer choices so it will be easier to figure out that E is not possible, but I am solving all the options to complete the solution)

A. b -> This can be true if numbers are in ascending order a,b,c or c,b,a => POSSIBLE

B. a - c -> Let's take values to prove it right. c = 1, b = 9, a=10, making a-c=9 which is b -> which is the median => POSSIBLE

C. a - b - c -> Let's take values to prove it right. c = 1, b = 9, a=19, making a - b - c=19-9-1=9 which is b -> which is the median => POSSIBLE

D. a + b - c -> Let's take values to prove it right. b = 1, c = 9, a=17, making a + b - c=17 + 1 - 9 = 9 which is c -> which is the median => POSSIBLE

E. a + b + c -> Now this can never be true as a,b,c are positive numbers so sum of a,b and c will always be greater than a,b,c => NOT POSSIBLE

So, Answer will be E
Hope it helps!

Watch the following video to Learn the Basics of Statistics

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Median is the central value

a, b and b are all positive integers. if we check the options, option E is a+b+c which will give us number greater than any of the three values. hence cannot be the median.

Answer --> Option E
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