Bunuel
An antique store has a collection of eight clocks. At a particular moment, the displayed times on seven of the eight clocks were as follows: 1:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm. If the displayed times of all eight clocks form an evenly spaced sequence (arithmetic progression), then what was the displayed time on the remaining clock?
A 1:53 pm
B 1:58 pm
C 2:18 pm
D 3:08 pm
E 5:08 pm
Deconstructing the QuestionThe problem asks for the missing clock time in a sequence.
Convert all times to minutes from a reference (e.g., 12:00 pm) to find the pattern.
Given Times:1:55 pm = 115 min
2:03 pm = 123 min
2:11 pm = 131 min
2:24 pm = 144 min
2:45 pm = 165 min
3:19 pm = 199 min
4:14 pm = 254 min
Step 1: Analyze DifferencesCalculate the difference between consecutive terms:
123 - 115 =
8131 - 123 =
8144 - 131 =
13165 - 144 =
21199 - 165 =
34254 - 199 =
55The sequence of differences is: 8, 8, 13, 21, 34, 55.
Notice the Fibonacci relationship for the later terms:
13 + 21 = 34
21 + 34 = 55
8 + 13 = 21
However, the beginning (8, 8) breaks the pattern. Working backwards from 13, the previous terms should be 5 and 3 (since 5+8=13 and 3+5=8).
The first gap of "8" in our data (between 1:55 and 2:03) is actually the sum of the missing
3 and
5 intervals. This implies the missing clock is inside this first interval.
Step 2: Find the Missing ValueWe need to split the interval between 1:55 pm and 2:03 pm.
Start with the smallest Fibonacci difference expected:
3.
1:55 pm + 3 minutes =
1:58 pm.
Check the next interval:
2:03 pm - 1:58 pm = 5 minutes.
This completes the Fibonacci difference sequence:
3, 5, 8, 13, 21, 34, 55.
Answer: B