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05 Aug 2021, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:55) correct
28%
(02:20)
wrong
based on 71
sessions
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Note: the diagram is not drawn to scale.
Lines AG, BF, and CE are parallel. If the height of B from AG is 12, and the height of C from BF is 8, then what is the height of C from AG?
A. 9
B. 12
C. 15
D. 16
E. 20
Attachment:
1.png [ 4.37 KiB | Viewed 2393 times ]
05 Aug 2021, 03:27
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Solution:
Refer to the picture:
parallel2.png [ 24.47 KiB | Viewed 2271 times ]
We are told that the height of B from AG is 12. Which means \(BH=12\).
We also know that the height of C from BF is 8. Which means \(CI=8\).
We are asked height of C from AG. This means we need the value of \(CJ=??\).
If we look closely, we will notice that length \(IJ\) will be the same as \(BH\) because the distance between 2 parallel lines remains the same throughout.
Thus \(IJ=BH=12\).
Hence \(CJ=CI+IJ=8+12=20\).
The right answer is Option E.
Refer to the picture:
Attachment:
parallel2.png [ 24.47 KiB | Viewed 2271 times ]
We are told that the height of B from AG is 12. Which means \(BH=12\).
We also know that the height of C from BF is 8. Which means \(CI=8\).
We are asked height of C from AG. This means we need the value of \(CJ=??\).
If we look closely, we will notice that length \(IJ\) will be the same as \(BH\) because the distance between 2 parallel lines remains the same throughout.
Thus \(IJ=BH=12\).
Hence \(CJ=CI+IJ=8+12=20\).
The right answer is Option E.
05 Aug 2021, 04:49
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since AG, BF, and CE are parallel height of C from AG =the height of B from AG + height of C from BF = 12 + 8 =20
(E) is the answer IMO
(E) is the answer IMO
Bunuel
