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Given: Ross can paint the walls of his dormitory in 12 hours. His friends, Ryan and Jack, each working alone can paint the same walls in 15 hours and t hours, respectively. On Sunday morning Ross starts to paint his dormitory walls alone and 4 hours later Ryan joins him. After another 4 hours Jack joins them. After that Ross, Ryan, and Jack together paint the wall in 20 minutes.

Asked: What is the value of t?

Ross can paint the walls of his dormitory in = 12 hours
Ryan can paint the same walls in = 15 hours
Jack can paint the same walls in = t hours

First 4 hours:
Work done by Ross alone = 4/12 = 1/3
Work remaining = 1 - 1/3 = 2/3

Second 4 hours:
Work done by Ross and Ryan = 4/12 + 4/15 = (20 + 16) /60 = 36/60 = 3/5 = .6
Work remaining = 2/3 - 3/5 = (10 - 9)/15 = 1/15

Last 20 minutes (1/3 hours) :
Work done by Ross, Ryan and Jack = 1/36 + 1/45 + 1/3t = 1/15
1/3t = 1/15 - 1/45 - 1/36 = 2/45 - 1/36 = (8-5)/180 = 3/180 = 1/60
3t = 60
t = 20 hours

IMO D
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given rate of Ross ; 1/12
Rate of Ryan ; 1/15 and rate of Jack 1/t
in 4 hours Ross does ; 1/12 * 4 ; 1/3 work
left with 2/3 work
later Ross & Ryan work together for 4 hours
total work done would be = 4* ( 1/12 +1/15 ) ; 4*9/60 ; 3/5
work left = 2/3-3/5 ; 10-9/15 ; 1/15
when all three work together for 20 mins ; 20/60 ; 1/3 hrs
1/3 *(1/12+1/15+1/t) ; 1/3 *(9t+60)/60 = 1/15
solve for t = 9t+60 =12t ; t= 20
option D

antoniogmat
Ross can paint the walls of his dormitory in 12 hours. His friends, Ryan and Jack, each working alone can paint the same walls in 15 hours and t hours, respectively. On Sunday morning Ross starts to paint his dormitory walls alone and 4 hours later Ryan joins him. After another 4 hours Jack joins them. After that Ross, Ryan, and Jack together paint the wall in 20 minutes. What is the value of t?

A. 4 hours
B. 8.5 hours
C. 15 hours
D. 20 hours
E. 25 hours
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4/12+ 4( 1/15+1/12) + 1/3( 1/15+1/12+1/t) = 1
ross alone work + ross jack work together + all 3 work for 20 minutes = 1( quantity of total work- say 1)
on solving, x = 20 hours

hence D
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