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\(\frac{(8!-7!*2!)}{8!}\) =\(\frac{ 3}{4}\)

Option (D) is correct
Bunuel
The 8 leaders of the G8 nations convene in Rome and stand in a row as they get ready to have some pictures of them taken by the press. What is the probability that the picture that the New York Times' editors will randomly select for publishing the next day is one in which Berlusconi is not standing next to Obama? (assuming that there are pictures of all possible standing arrangements).

A. 1/8
B. 1/4
C. 1/2
D. 3/4
E. 7/8
 
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1-(7!*2)/8!

1-1/4

=3/4

D
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Order Matters here.

There are 8 PERMUTATIONS in total = 8!

Now, let's consider O and B together = O B _ _ _ _ _ _

Number of ways in which O and B are together = 7!*2 (Multiply by 2 to account for the arrangements between O and B)

Ways in which O and B do not stand together = 1-7!*2/8! = 1-1/4 = 3/4
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