If A?B = (A + B)/B, and C@ = C + 3, what is the value of 9@(?3)

Question

If  A \blacklozenge B = \frac{A +B}{B} , and  C \clubsuit = C+3 , what is the value of  (9 \clubsuit ) \blacklozenge 3  ?

A. 1

B. 2

C. 3

D. 4

E. 5

Abhishek009 · Answer

(9 \clubsuit ) = 9 + 3 = 12

(9 \clubsuit ) \blacklozenge 3 = 12\blacklozenge 3 = \frac{12 + 3}{3} = 5  , Thus Answer must be (E) 5

100mitra · Answer

C = 9
 = C + 3
 = 9 + 3 
 = 12

A = 12, B = 3

\frac{A + B }{ B}  =  \frac{12 + 3 }{ 3}  =  \frac{15 }{ 3}   = 5 = Option E

BrushMyQuant · Answer

C \clubsuit = C+3

=>  9 \clubsuit = 9+3  = 12

=>  (9 \clubsuit ) \blacklozenge 3  =  12 \blacklozenge 3

A \blacklozenge B = \frac{A +B}{B}

=>  12 \blacklozenge 3 = \frac{12 +3}{3}  =  \frac{15}{3}  = 5

So,  Answer will be E 
Hope it helps!

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