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abhijay1234
The probability that the number of guests at a theme park will exceed 10,000 on Saturday is 0.6. The probability that the number of guests at the same theme park will exceed 10,000 on Sunday is 0.3. Assuming that the numbers of guests on each day are independent, what is the probability that the number of guests exceeds 10,000 on Saturday, or on Sunday, but not both?

A. 0.18
B. 0.46
C. 0.54
D. 0.72
E. 0.9

Probability fo Guest count exceeding 10000 on Saturday = 0.6
Probability fo Guest count NOT exceeding 10000 on Saturday = 1-0.6 = 0.4

Probability fo Guest count exceeding 10000 on Sunday = 0.3
Probability fo Guest count NOT exceeding 10000 on Saturday = 1-0.3 = 0.7

Probability of Guest count exceeding 1000 on nboth saturday and Sunday = 0.6*0.3 = 0.18
Probability of Guest count NOT exceeding 1000 on both saturday and Sunday = 0.4*0.7 = 0.28

Imwanted probability = 0.18+0.28 = 0.46

Probability of Favourable outcomes (exceeding on exactly one of teh saturday and Sunday) = 1-0.46 = 0.54

Answer: Option C
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p (Both) = 0.3 X 0.6 = 0.18

P (Neither) = 0.4 X 0.7 = 0.28

In all other cases one or the other will be true

Hence
P (either) = 1 -(0.18 + 0.28) = 0.54
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P(Exactly one of the two events) for a two set is given by P(A)+P(B) - 2*P(A intersection B)
since given events are independent so P(A intersection B)=P(A)*P(B)=0.6*0.3=0.18
so, P( E1)=0.9-0.36=0.54
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The probability of exactly one event happening is P(A)(1-P(B))+ P(B)(1-P(A)

so,
0.6*(1-0.3)+0.3*(1-0.6) = 0.42+ 0.12 + 0.54
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P(sat or sun) = P(sat) + P(sun) - 2*P(sat and sun)
=0.6 + 0.3 - (2*0.6*0.3)
=0.54
Option C
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