Its_me_aka_ak
stne
Bunuel
Using each letter of the word ZEBRA only once how many one, two, three, four and five-letter words can be created ?
A. 20
B. 60
C. 100
D. 150
E. 325
\(1\) letter words : \(5C1=5\)
\(2\) letter words : \(5C2∗2!=10\)
\(3\) letter words : \(5C3∗3!=60\)
\(4\) letter words : \(5C4∗4!=120\)
\(5\) letter words : \(5C5∗5!=120\)
Total \(=5+10+60+120+120=325\)
Ans E
Hope it's clear.
why do we multiply 2! onto 5C2 and all?
Hi
Its_me_aka_ak5C2 is the number of ways to select 2 things from 5 things.
Note : Doing this does not consider different arrangements of the selected two things.
For e.g. = suppose we have A,B, C, D,E now how many ways to select two things out of 5 things ? This can be done in 5C2 ways. That's 10 ways.
AB
BC
DE
AE
BE
CE
AC
AD
BD
CD
However in the given question since " words" need to be created hence AB and BA will be different words.
But doing 5C2 will not give AB and BA as two different words, it will only one word. To consider all the possibilities we need to multiply by the respective letters in the words.
In this question " Arrangement " also needs to be considered and not only selection.
Hence if we consider AB and BA as two arrangements then in total we will have 20 arrangements.
Hence we multiply by the respective number , because if word consists of two letters then number of ways to arrange them is 2!
If word consists of 3 letters then the number of ways to arrange them is 3!
Basically what we are doing is called permutation.
Hence we multiply by the number of alphabets in the words.
Note this is only in case all the alphabets are distinct, if alphabets are repeated then a different process needs to be followed.
you can visit the permuation and combination topic in gmat club and learn more about this.
Hope it helps.