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Bunuel
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pudu
a=-5d then how it is possible to get all terms are positive? even if d =-1 then too we have negative terms...The answer is D...if not please correct me.

pudu

I guess you're referring to statement 3.

Note, the statement doesn't state that the terms are positive. Rather, it states that - "All terms are non negative"

Hence, we now have the possibility of all terms = 0. So, if d = 0, all the terms can be zero in the series.

Hope that clarifies!
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I understood if it is zero then it can be non-negate, but if it is zero then how can be AP.
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pudu
a=-5d then how it is possible to get all terms are positive? even if d =-1 then too we have negative terms...The answer is D...if not please correct me.

pudu

I guess you're referring to statement 3.

Note, the statement doesn't state that the terms are positive. Rather, it states that - "All terms are non negative"

Hence, we now have the possibility of all terms = 0. So, if d = 0, all the terms can be zero in the series.

Hope that clarifies!

thanks, but still have doubt. I agreed with you d can be zero, but it is so then how it can be an AP
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5,4,3,2,1,0,-1,-2,-3,-4,-5,-6,-7,-8,-9,-10 - accounts for statements 1 and 2.

Also, all the terms in the sequence can be 0.

So answer is E
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please someone helps me.if all the terms are zero then how it should be AP
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pudu
please someone helps me.if all the terms are zero then how it should be AP

pudu

A set of numbers is in arithmetic progression if the difference between consecutive terms (common difference) is constant. That difference can be positive, negative or zero.

For example: 1,1,1,1 is in AP with common difference 0.

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-5d.-4d,-3d......

so if d=0 then statement 3 is true...right?
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Asked: If the sum of the first 11 terms of an arithmetic progression consisting 16 terms is zero, then which of the following COULD be true ? (An arithmetic progression is a sequence of numbers such that the difference between the consecutive terms is constant)

Let the sequence be a-8d, a-7d, a-6d, ....a-d, a, a+d, .... a+7d.

The same of first 11 terms = a-8d + a-7d + a-6d + ...+a + a+d + a+2d = 11a - 33d = 0
a = 3d

I. 11th smallest term is zero :
11th smallest term = a +2d = 3d + 2d = 5d
If d=0
COULD BE TRUE

II. 6th largest term is zero
6th largest term = a - 3d = 0
TRUE

III. All terms are non negative
a - 8d = 3d - 8d = - 5d
Which may be positive or negative
If a=10;d=-1
COULD BE TRUE

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


IMO E
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but sir if we take sum of the first 11 terms as zero then we get a=-5d and we get two sequences by putting d=1 and d=-1. so naturally I and II are correct. My question is only about the statement III. From how we get that sequence?
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Bunuel
If the sum of the first 11 terms of an arithmetic progression consisting 16 terms is zero, then which of the following COULD be true ? (An arithmetic progression is a sequence of numbers such that the difference between the consecutive terms is constant)

I. 11th smallest term is zero
II. 6th largest term is zero
III. All terms are non negative

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


 


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Bunuel could you please share the official answer to this question? Thank you in advance.
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