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Bunuel
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 21 Nov 2022, 02:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

35% (medium)

Question Stats:

69% (01:36) correct 31% (01:55) wrong based on 170 sessions

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If \(x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!\), what is the remainder when x is divided by 20?

A. 15
B. 14
C. 13
D. 12
E. 11


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C
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sumit99kr
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 21 Nov 2022, 14:53
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Fastest approach-- all numbers after 4! are divisible by 20.

So remainder will be-----
(1!+2!+3!+4!) /20 = 33/20.
Remainder is 13.

Hence C is the correct choice.

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Rabab36
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 21 Nov 2022, 03:59
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I HAVE MARKED OPTION C

BUT TOOK TIME

ANYONE WITH FAST SOLUTION

EVEN NOT SURE WITH ANS
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 21 Nov 2022, 04:39
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Rabab36
To get 20 in the factorial we need one 5 and 4, it will only start from 5!, so only consider the factorials before 5!, i followed the same procedure and ticked C in 57 seconds

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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 27 Nov 2022, 02:36
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all numbers after 4! are divisible by 20

so reminder will be sum of remainder from 1!/20 + 2!/20 + 3!/20 + 4!/20 = 1 + 2 + 6 + 4 = 13
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 27 Nov 2022, 05:21
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Bunuel
If \(x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!\), what is the remainder when x is divided by 20?

A. 15
B. 14
C. 13
D. 12
E. 11

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The given choices have different unit digits, so just knowing units digit will also help.
Every term after 4! will have 0 as units digit.
1!+2!+3!+4! will give 1+2+6+24, so 1+2+6+4 or 13

The units digit may just save 5 to 10 seconds here but same could be useful elsewhere.
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If x = 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! + 10!, what is the 02 Feb 2025, 04:37
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