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Bunuel
There are 5 apples in a bag. 4 apples are good but 1 apple is rotten. If you take out 2 apples from the bag, what is the probability that 1 apple selected is rotten?

A. \(\frac{1}{3}\)

B. \(\frac{1}{4}\)

C. \(\frac{2}{5}\)

D. \(\frac{3}{5}\)

E. \(\frac{1}{7}\)

If we label all the apples from 1 to 5 and the 5th apple is rotten, there are 20 possible ways to take out 2 apples. If we take out the 5th apple first, we can then take out the second apple from the remaining 1-4 apples, which gives us 4 possible ways. If we take out the rotten apple second, there are also 4 possible ways to take out the first apple. Therefore, the probability of selecting a rotten apple as the second one is 8/20 or 2/5.

So C
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we can also do [(4c1*1c1) + (4c2*1c0)] / 5c2 = 2/5
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Step-by-Step Solution
Find the total number of ways to pick 2 apples from 5:

Using combinations, choosing 2 apples out of 5 gives:

Total ways = (5 x 4) / (2 x 1) = 10 ways.

Find the number of ways to get exactly 1 rotten and 1 good apple:

There is only 1 rotten apple, and we need to choose it: 1 way.

There are 4 good apples, and we need to choose 1 of them: 4 ways.

Total favorable outcomes = 1 x 4 = 4 ways.

Calculate the probability:

Probability = Favorable outcomes / Total outcomes = 4 / 10 = 2 / 5.

Answer Choice
C. 2/5
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