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The median of nine positive integers is x and the range is 8 more than 09 Nov 2023, 16:26
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The median of nine positive integers is x and the range is 8 more than the median. If the greatest of the integers is 15, which of the following represents the least of the integers?

A. 8 - x
B. x - 8
C. 7 - x
D. x - 7
E. x - 15

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The median of nine positive integers is x and the range is 8 more than 09 Nov 2023, 22:32
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median is x or say 5th integer
15-smallest integer = x+8
Smallest integer = 7-x

Option C

The media of nine positive integers is x and the range is 8 more than the median. If the greatest of the integers is 15, which of the following represents the least of the integers?

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The median of nine positive integers is x and the range is 8 more than 16 May 2024, 10:58
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Greatest number: 15
Least: Y (we need to determine its value)
Range: x+8

And Range = Greatest - Lesser
15 - y = x+8
7 - x = y
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The median of nine positive integers is x and the range is 8 more than 27 Mar 2024, 07:20
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Why could the answer not be D?
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The median of nine positive integers is x and the range is 8 more than 15 Dec 2024, 04:48
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We are given that the median of nine positive integers is x, the range is 8 more than the median, and the greatest integer is 15. We need to find which of the following represents the least of the integers.

Step 1: The median of nine integers is x. Since there are 9 integers, the median is the 5th number when the integers are arranged in increasing order.

- The range is defined as the difference between the greatest and least integers.
- The greatest integer is 15.
- The range is 8 more than the median, so:

Range = 15 - least integer = x + 8

Step 2: Express the range in terms of the least integer
The range is the difference between the greatest and least integer, so we have:
15 - least integer = x + 8.

Let the least integer be y. Then: 15 - y = x + 8

Solving for y: y = 15 - (x + 8) = 15 - x - 8 = 7 - x


Therefore, the correct option is: 7 - x

Option C
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The median of nine positive integers is x and the range is 8 more than 04 Oct 2025, 10:12
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Very detailed info, thanks:)
Tushaar121
We are given that the median of nine positive integers is x, the range is 8 more than the median, and the greatest integer is 15. We need to find which of the following represents the least of the integers.

Step 1: The median of nine integers is x. Since there are 9 integers, the median is the 5th number when the integers are arranged in increasing order.

- The range is defined as the difference between the greatest and least integers.
- The greatest integer is 15.
- The range is 8 more than the median, so:

Range = 15 - least integer = x + 8

Step 2: Express the range in terms of the least integer
The range is the difference between the greatest and least integer, so we have:
15 - least integer = x + 8.

Let the least integer be y. Then: 15 - y = x + 8

Solving for y: y = 15 - (x + 8) = 15 - x - 8 = 7 - x


Therefore, the correct option is: 7 - x

Option C
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The median of nine positive integers is x and the range is 8 more than 05 Oct 2025, 22:20
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because we are subtracting 15- (x+8) -> this would give us 7-x. not x-7.
wfinneran
Why could the answer not be D?
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