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Bunuel
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Bunuel
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edthehead7
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edthehead7
­Hey Bunuel -- I'm curious if you could describe or write out that first step of simplification?

I went a different route but it felt messy, and your path seems simpler but I'm a bit conufsed how you factored out (xy)^2 from both sides of the numerator... thank you 
­
­\(x^6y^2 - x^2y^6 = \)

­\(=x^4 (x^2y^2) - (x^2y^2)y^4 = \)

­\(= (x^2y^2)(x^4 - y^4) \)­
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Does
­\(=1\frac{1}{8}=\) mean 1+1/8?

Bunuel


­

­\(\frac{x^6y^2 - x^2y^6}{x^2 + y^2} = \)

­\(=\frac{(xy)^2(x^4 - y^4)}{x^2 + y^2} = \)

­\(=\frac{(xy)^2(x^2 - y^2)(x^2 + y^2)}{x^2 + y^2} = \)

­\(=(xy)^2(x^2 - y^2)= \)

­\(=(\frac{3}{2}*\frac{1}{2})^2((\frac{3}{2})^2 - (\frac{1}{2})^2) = \)

­\(=(\frac{9}{16})(2) = \)

­\(=\frac{9}{8}=\)

­\(=1\frac{1}{8}=\)

Answer: ­D.­
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Does
­\(=1\frac{1}{8}=\) mean 1+1/8?


_________________________
Yes.
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can anyone share some questions on the similar topic?
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