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DrAnkita91
please can you tell me how did you get the answer of it?

­Eight people have to go to the hospital during a particular week. What is the probability that on at least one of the days, at least two people will go to the hospital?

A. 0.2
B. 0.3
C. 0.7
D. 0.8
E. 1

There are 7 days and 8 people. Thus, it's not possible to distribute them in such a way that on each day less than 2 people go to the hospital. Therefore, the probability that on at least one of the days, at least two people will go to the hospital is 1.

Answer: A.­
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Deconstructing the Question

We have 8 people and only 7 days in the week.

We want the probability that on at least one day, at least 2 people go to the hospital.

The fastest way is to think about the complement: no two people go on the same day. But that would require all 8 people to go on different days.

That is impossible, because there are only 7 days.

Step-by-step

To avoid having at least 2 people on the same day, each of the 8 people would need a different day.

But there are only 7 days available.

So once 7 people are assigned to different days, the 8th person must share a day with someone else.

Therefore, at least one day must have at least 2 people.

So the probability is:

\(1\)

Answer: E) 1
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