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Victor314

Given: ­State X has 77 acres designated as wilderness, which is 0.0003 percent of its total acreage.
Asked: Which of the following expresses the total acreage of State X?

The total acreage of State X = \(\frac{77}{.0003%} = \frac{7700}{.0003} = \frac{77000000}{3} = \frac{10^6*77}{3}\)

IMO E­
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I got it in the OG Practice Test #4­
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Bunuel
I got it in the OG Practice Test #4­
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­Thank you. Updated the tag.
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Victor314
­State X has 77 acres designated as wilderness, which is 0.0003 percent of its total acreage. Which of the following expresses the total acreage of State X?

A. \(3(10^4)(77)\)

B. \(3(10^6)(77)\)

C. \(\frac{(10^2)(77)}{3}\)

D. \(\frac{(10^4)(77)}{3}\)

E. \(\frac{(10^6)(77)}{3}\)­

Source: GMAT Focus Prep
Wilderness = (0.00003/100)*­Total Acerage
i.e. Total Acerage = Wilderness * 1000/0.0003 = \(77*10^2/(3*10^{-4}) = 77*10^6/3\)

Answer: Option E­
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