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IMO C

303/25=121.2 ~121

Option C
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A church collected exactly $303 from its members during a service. If each member contributed at least $2.50, what is the greatest number of members that could have attended this particular service?­

Answer:
Total amount: 303$
each member: atleast 2.5$ (it might be the case that someone have paid 3$, 2.8$ or anything more than 2.5$)
Lets assume "n" is the max. number of members

Therefore: 2.5(atleast) * n = 303
n= 303/2.5
n=121.2 (someone might have paid 3 $)
there maximum number of members is 121 (2.5*120+ 3*1= 303)    (120 members paid 2.5$,1 member paid 3$)
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