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We need to find the tens digit of \(7^{202}\)

Last Two Digits of 7 follow following pattern

  • Last two digits of 7^1 = 07
  • Last two digits of 7^2 = 49
  • Last two digits of 7^3 = 49*7 = 43
  • Last two digits of 7^4 = 43*7 = 01
  • Last two digits of 7^5 = 01*7 = 07
  • Last two digits of 7^6 = 07*7 = 49

=> We have a cycle of 4
=> 202 = 200 + 2
=> \(7^{202}\) will have the same last two digits as \(7^{2}\) = 49
=> Tens' digit = 4

So, Answer will be D
Hope it helps!

Link to Theory for Last Two digits of exponents here.

Link to Theory for Units' digit of exponents here.
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