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24 Aug 2025, 22:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:36) correct
19%
(01:51)
wrong
based on 119
sessions
History
Date
Time
Result
Not Attempted Yet
A bowl of fruit contains 14 apples and 23 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples?
(A) 3
(B) 6
(C) 14
(D) 17
(E) 20
Source Veritas Prep
(A) 3
(B) 6
(C) 14
(D) 17
(E) 20
Source Veritas Prep
25 Aug 2025, 00:12
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Taking no of oranges to be removed as x
Total no of fruits = 14+23-x = 37-x
Asked as 14/(37-x) = 0.7
Solving this we get x = 17
Hence D is the answer
Total no of fruits = 14+23-x = 37-x
Asked as 14/(37-x) = 0.7
Solving this we get x = 17
Hence D is the answer
Bunuel
25 Aug 2025, 10:16
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just find 14 is 70% of what number
(14/x)*100=70
x=20
14+6=20 hence number of oranges should be 6
So oranges which needs to be removed is 23-6-17 (D)
(14/x)*100=70
x=20
14+6=20 hence number of oranges should be 6
So oranges which needs to be removed is 23-6-17 (D)
Bunuel
