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Difficulty:
35%
(medium)
Question Stats:
61% (00:57) correct
39%
(01:13)
wrong
based on 119
sessions
History
Date
Time
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Not Attempted Yet
The kinetic energy of a particle is proportional to the square of its velocity. If the velocity increases by 20%, then the kinetic energy will increase by
A) 40%
B) 44%
C) 140%
D) 144%
E) 400%
A) 40%
B) 44%
C) 140%
D) 144%
E) 400%
04 Sep 2025, 04:31
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KE is proportional to square of velocity
So when velocity becomes 1.2V then square of it will be 1.44 times
Thus it means K will increase 1.44-1 = 0.44 times which is 44%
So when velocity becomes 1.2V then square of it will be 1.44 times
Thus it means K will increase 1.44-1 = 0.44 times which is 44%
srosh2000
04 Sep 2025, 23:35
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srosh2000
\(KE = k*V^2\) (where \(k\) is a proportionality constant)
\(V' = 1.2V\) .........(i)
\(KE' = k*(V')^2\)
\(KE' = k*(1.2V)^2\) ...........(from i)
\(KE' = k*1.44*V^2\)
% increase in KE = \(\frac{ KE' }{ KE}\) - 1
= \(\frac{1.44*k*V^2}{k*V^2}\) - 1
= \(1.44-1\) = \(0.44\)
= \(44\)%
Answer B.
