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03 Nov 2025, 00:42
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Difficulty:
55%
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Question Stats:
59% (01:57) correct
41%
(01:40)
wrong
based on 140
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In a class of 40 students, 12 are left-handed and the other 28 are right-handed. If two students are chosen at random, what’s the probability that one is left-handed and one is right-handed?
A. 21/100
B. 14/65
C. 21/50
D. 28/65
E. 37/65
A. 21/100
B. 14/65
C. 21/50
D. 28/65
E. 37/65
03 Nov 2025, 04:27
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Here is the quick solution of the question:-
Total students = 40
in which left handed = 12
and right handed = 28
total ways to choose 2 would be = 40C2 = (40*39)/2 = 780
favorable = 1 left and 1 right
12C1 * 28C1 = 12 * 28 = 336
So,
P = 336/780 = 28/65
Final answer :- Option(D)
Total students = 40
in which left handed = 12
and right handed = 28
total ways to choose 2 would be = 40C2 = (40*39)/2 = 780
favorable = 1 left and 1 right
12C1 * 28C1 = 12 * 28 = 336
So,
P = 336/780 = 28/65
Final answer :- Option(D)
Bunuel
03 Nov 2025, 05:20
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Given there are 40 students, 12 left handed (LH) and 28 right handed (RH)
Probability of choosing a left handed and one right handed = P(LH, RH) + P(RH, LH)
= (12/40 x 28/39) +( 28/40 x 12/39)
= 28/65 (Option D)
Probability of choosing a left handed and one right handed = P(LH, RH) + P(RH, LH)
= (12/40 x 28/39) +( 28/40 x 12/39)
= 28/65 (Option D)
