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60^2 = 3600
Prime Factorizarion of 3600 => 3^2 * 5^2 * 2^4

Now, for finding out the number of factors of 60^2 that are multiples of 3, we will have to ensure that there is atleast 1 multiple of 3 (except for this, there is no other constraint as such)

Hence, total number of such factors = 2*3*5 = 30 (Option E)
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Prime factorization of 60^2:
(2×3×2×5)^2 = 2^4×3^2×5^2

Now the total no of factors are:
(4+1)(2+1)(2+1)= 45
But we want all the factors of 3
So we need to subtract the factors of 3^0
5×1×3=15

Therefore we get =45-15 =30

Hence option E
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ExpertsGlobal5
How many factors of 60^2 are multiples of 3 ?

A. 10
B. 12
C. 15
D. 20
E. 30


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60^2 = 60*60 = 2*3*2*5*2*3*2*5 = 2^4 * 3^2 * 5^2

Multiple of 3 = 3* ( 2^4 * 3 * 5^2) = 3*K

The number of factors of ( 2^4 * 3 * 5^2)

= (4+1)*(1+1)*(2+1)

= 5*2*3

= 30

Option E
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How many factors of 60^2 are multiples of 3 ?

A. 10
B. 12
C. 15
D. 20
E. 30
Video explanation:

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ExpertsGlobal5
How many factors of 60^2 are multiples of 3 ?

A. 10
B. 12
C. 15
D. 20
E. 30


Experts' Global
This Daily Butler Question was provided by Experts' Global
Sponsored


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factor multiple of 3 = Total factor - factors not a multiple of 3

factors not a multiple of 3

factors of 2^4 * 5^2 = 5 * 3 = 15 factors

Total factors

3^2 2^4 * 5^2 = 3* 5 * 3 = 45 factors


45 - 15 = 30 factors (option e)
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