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29 Jun 2026, 14:22
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
72% (02:44) correct
28%
(02:50)
wrong
based on 187
sessions
History
Date
Time
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Not Attempted Yet
Gaspar walked from his house to his office at 4 km/h and arrived 12 minutes late. If he had run at 16 km/h, he would have arrived 9 minutes early. At what speed should he have walked or run to arrive exactly on time?
A. 7 km/h
B. 8 km/h
C. 9 km/h
D. 10 km/h
E. 12 km/h
A. 7 km/h
B. 8 km/h
C. 9 km/h
D. 10 km/h
E. 12 km/h
29 Jun 2026, 20:32
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Let the distance be D km.
0.2 + 0.15 = 0.35 hours
Now,
D/4 − D/16 = 0.35
⇒ D(1/4 − 1/16) = 0.35
⇒ D × 3/16 = 0.35
⇒ D = (0.35 × 16)/3 = 28/15 km
Scheduled travel time:
D/4 − 0.2 = (28/15)/4 − 0.2 = 7/15 − 3/15 = 4/15 hours
Required speed:
Speed = Distance ÷ Time
= (28/15) ÷ (4/15)
= 7 km/h
Answer: A. 7 km/h.
- At 4 km/h, Gaspar is 12 min (0.2 h) late.
- At 16 km/h, he is 9 min (0.15 h) early.
0.2 + 0.15 = 0.35 hours
Now,
D/4 − D/16 = 0.35
⇒ D(1/4 − 1/16) = 0.35
⇒ D × 3/16 = 0.35
⇒ D = (0.35 × 16)/3 = 28/15 km
Scheduled travel time:
D/4 − 0.2 = (28/15)/4 − 0.2 = 7/15 − 3/15 = 4/15 hours
Required speed:
Speed = Distance ÷ Time
= (28/15) ÷ (4/15)
= 7 km/h
Answer: A. 7 km/h.
30 Jun 2026, 07:27
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Let us calculate the distance first.
We know, Distance=\(\frac{Speed1*Speed2}{(S1-S2)}\)* time difference
So, D= \(\frac{4*16}{12}*\frac{21}{60}\)
=\( \frac{28}{15}\) km
Let us calculate the required time.
Time= Distance/speed
t= \(\frac{28}{(15*4)} * 60 \) (to convert in minutes)
t= 28 minutes
As in 4 km/h speed makes him 12 minutes late so the correct time will be 28-12=16 minutes
To reach on 28 minutes, Gasper walks in 4 km/h
To reach on 1 minute, Gasper should walk in 4*28 km/h
To reach on 16 minutes, Gasper should walk in\(\frac{ 4*28}{16 }\)km/h = 7 km/h
So, the answer is A 7 km/h.
We know, Distance=\(\frac{Speed1*Speed2}{(S1-S2)}\)* time difference
So, D= \(\frac{4*16}{12}*\frac{21}{60}\)
=\( \frac{28}{15}\) km
Let us calculate the required time.
Time= Distance/speed
t= \(\frac{28}{(15*4)} * 60 \) (to convert in minutes)
t= 28 minutes
As in 4 km/h speed makes him 12 minutes late so the correct time will be 28-12=16 minutes
To reach on 28 minutes, Gasper walks in 4 km/h
To reach on 1 minute, Gasper should walk in 4*28 km/h
To reach on 16 minutes, Gasper should walk in\(\frac{ 4*28}{16 }\)km/h = 7 km/h
So, the answer is A 7 km/h.
