If positive integer k is divided by 6, the quotient is m and

Question

If positive integer k is divided by 6, the quotient is m and the remainder is 2, then which of the following must be true?

I. k + m is even

II. k cannot be a prime number

III. k is divisible by 4

A. None
B. I
C. II
D. III
E. I and II only

virtualanimosity · Answer

K=6m+2 ( dividend = quotent*divisor+ remainder
take a few example 
k=2 ,m=0
k=8, m=1
k=14,m=2

thus ans if none of these 
ans.a

ezinis · Answer

k = 6m+2 = 2(3m+1)
I. k + m = 2(3m+1) + m => even if only m is even, however m can be odd => not always true
II. k can not be a prime: not always true:
 m=0 => k=2 : a prime
III. not true if m is even

Ans: none of the above

sdas · Answer

Question is which "must be true"

So Ans is C (K cannot be prime, as primes cannot be divisible by 6 with remainder as 2)

Bunuel · Answer

That's not correct.

If positive integer k is divided by 6, the quotient is m and the remainder is 2, then which of the following must be true?

I. k + m is even
II. k cannot be a prime number
III. k is divisible by 4

A. None
B. I
C. II
D. III
E. I and II only

Positive integer k is divided by 6, the quotient is m and the remainder is 2 can be expressed as  k=6m+2 :

If  m=0 , then  k=2=prime  --> discard II and III.
If  m=1 , then  k=8  -->  k+m=9=odd  --> discard I.

Answer: A.

Hope it's clear.

sdas · Answer

Thanks Bunuel to rectify my careless approach. Of course 2 is prime...
+1 to you

gracie · Answer

I. not true:
 let k=8
 8=6*1+2
 8+1=9 (odd)
II. & III. not true:
 let k=2
 2=6*0+2
 2 is prime and not divisible by 4
A

bumpbot · Answer

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If positive integer k is divided by 6, the quotient is m and

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If positive integer k is divided by 6, the quotient is m and

Prep Toolkit

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