A batch of cookies was divided amomg 3 tins: 2/3 of all the

Question

A batch of cookies was divided amomg 3 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7

A. 15/2
B. 9/4
C. 5/9
D. 7/5
E. 9/7

umeshkathuria · Accepted Answer

Let Total no. of cookies = 12 (LCM(3,4))
Cookies in Blue +Green Tin = (2/3)*12 = 8 
Cookies in Red Tin = 12-8 = 4 
Cookies in Blue tin = (1/4)*12 = 3 
Cookies in Green Tin = 8-3 = 5 
Green/other(other than Blue) = 5/(4+5) = 5/9 (C)

Bunuel · Answer

# of cookies - X

2/3 of all the cookies were placed in either the blue or the green tin:  B+G=\frac{2}{3}*X 
The rest were placed in the red tin:  R=\frac{1}{3}*X 
1/4 of all the cookies were placed in the blue tin:  B=\frac{1}{4}*X .

What fraction of the cookies that were placed in the other tins (other then blue, or in Green and Red) were placed in the green tin:  \frac{G}{G+R}=?

B+G=\frac{2}{3}*X  and  B=\frac{1}{4}*X ; -->  \frac{1}{4}*X+G=\frac{2}{3}*X ; -->  G=\frac{5}{12}*X .

\frac{G}{G+R}=(\frac{5}{12}*X)/(\frac{5}{12}*X+\frac{1}{3}*X)=\frac{5}{9}

Answer: C (5/9)

GMAT TIGER · Answer

Not a clear question! How one can infer/imply "other tins" mean "green + red tins"? Is that the massage the question supplying? How "other tins" is not mean "blue + red tins"?

Just to get the idea about the question i..e. how precisely and correctly the quesion is designed? Is it a question unnecessarily designed to be a tough or is it really tough?

For me, its not a standard GMAT level question.

Bunuel · Answer

If 1/4 of all the cookies were placed in the  blue tin , what  fraction that were placed in the other tins  were placed  in the green tin ?

I think that the question implies that  other tins then blue , as previously the stem in the same sentence was describing the fraction in blue tin.

I don't know the source but for me this could be the GMAT question.

shrouded1 · Answer

B + G = 2/3
R = 1 - 2/3 = 1/3
B = 1/4
So G = 2/3 - 1/4 = 5/12
G/(G+R) = G/(1-B) = (5/12)/(3/4) = 5/9

onedayill · Answer

How did u assumed that it has to be G/(G+R) instead of (B+R) ?
Can you please explain ?

shrouded1 · Answer

The question says 1/4th were placed in the blue tin, what percentage of the ones placed in the other tins ....

So other tins ==> Green + Red

mvictor · Answer

my approach:
say there are 12 cookies.
8 were in B and Green, and 4 were in red.
we need to put only 1/4 in blue, or 3 cookies. that leaves us with 9 remaining cookies.
since we need a fraction X/9, we can easily eliminate A, B, D, and E.
moreover, since in green tin maximum can be 9 remaining cookies, we would get 9/9, or 1.
A - 15/2 = 7.5 way more than needed.
B - 9/4 - 2.25 - no.
C - looks ok
D - >1 so no
E - > 1 so no.

NTA · Answer

"what fraction of the cookies that were placed in the other tins were placed in the green tin" can anyone explain this line please?

kawal27 · Answer

hi,
they want to say other cookies than in blue tin , means cookies from green and red tin = 4+5 = 9

kawal27 · Answer

cookies divided among 3 tins 
2/3 = 8/12 = cookies place in green or blue tin.
rest means 1/3 = 4/12 place in red tin.
 now if 1/4 = 3/12 cookies place in blue tin, means 8/12-3/12=5/12 place in green tin.

now other than cookies from blue tin what faction of cookies were place in green tin
means cookies from green and red tin = 5+4 =9

5 out of 9 cookies place in green tin

ANS:C

ManishaPrepMinds · Answer

Question is not worded Properly and to me, it seems that it is not a standard GMAT question

JHTIPU18 · Answer

Source - Kaplan 800

There is no error in this question.
Little grammatical confusion with if-clauses. 
here,
if clauses identify the total cookies in a blue tin, the independent clause refers to the other tins or nonblue in the last sentence. if u really understand the if clauses, you will definitely understand the question.

there is no error in the question.

GMATGuruNY · Answer

Let the total number of cookies = the LCM of the two denominators in the prompt = 12
Since 2/3 of the cookies are placed in the blue or green tin,  B+G = \frac{2}{3} * 12 = 8 
Since 1/4 of the cookies are placed in the blue tin,  B = \frac{1}{4} * 12 = 3

What fraction of the cookies that were placed in the other tins were placed in the green tin? 
other tins  = total - B = 12-3 = 9 
 G = (B+G) - B = 8-3 = 5 
 \frac{green}{other} = \frac{5}{9}

C

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A batch of cookies was divided amomg 3 tins: 2/3 of all the

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