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Posts: 56
Updated on: 14 Jul 2012, 02:00
Originally posted by barakhaiev on 20 Nov 2009, 04:14.
Last edited by Bunuel on 14 Jul 2012, 02:00, edited 1 time in total.
Last edited by Bunuel on 14 Jul 2012, 02:00, edited 1 time in total.
Edited the question and added the OA.
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A train traveling at a constant speed down a straight track crosses a certain line on the track. If the rear wheels of the train cross the line 2 seconds after the front wheels, and the centers of the rear and front wheels are 100 feet apart, which of the following expresses the speed of the train in miles per hour?
1 mile = 5280 feet
(A) \((100/5280)(60^2/2)\)
(B) \((100/5280)(60/2)\)
(C) \((100/5280)(2/60^2)\)
(D) \((100/60^2)(5280/2)\)
(E) \((100/60)(5280/2)\)
1 mile = 5280 feet
(A) \((100/5280)(60^2/2)\)
(B) \((100/5280)(60/2)\)
(C) \((100/5280)(2/60^2)\)
(D) \((100/60^2)(5280/2)\)
(E) \((100/60)(5280/2)\)
barakhaiev
Speed of the train would be 100/2 feet per second, as it covers the distance of 100 feet in 2 seconds.
We should transform this to miles per hour:
100 feet=100/5280 miles;
2 seconds=2/60^2 hours;
Hence we would have (100/5280)/(2/60^2)=(100/5280)*(60^2/2) miles per hour.
Answer: A.
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General Discussion
flgators519
Joined: 25 Oct 2009
Last visit: 05 Sep 2014
Posts: 24
Affiliations: University of Florida Alumni
Schools:Wharton, Booth, Stanford, HBS
Posts: 24
agree. 50 feet per second * 60 (convert to minutes) * 60 (convert to hours) this gives you feet per hour. Divide by 5260 = Miles per hour
Bunuel
Check other Conversion problems to practice in Special Questions Directory.
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Posts: 30
Hi
I am still unable to understand how the distance covered is 100/2.
The front wheel crosses say in 4 mins ( imagine half of the wheel crossed). Now it has to cover some distance till rear wheel crosses.
We can say that rear wheel crosses as soon as some part of wheel crosses line or half rotation ( distance till center of wheel ) crosses the line,
How are we concluding that 100 is the distance being traveled by wheels.
Somehow unable to imagine the problem.
Can someone please explain?
I am still unable to understand how the distance covered is 100/2.
The front wheel crosses say in 4 mins ( imagine half of the wheel crossed). Now it has to cover some distance till rear wheel crosses.
We can say that rear wheel crosses as soon as some part of wheel crosses line or half rotation ( distance till center of wheel ) crosses the line,
How are we concluding that 100 is the distance being traveled by wheels.
Somehow unable to imagine the problem.
Can someone please explain?
Posts: 3
seemachandran
Hello,
100/2 is not the distance, it is the rate of speed.
Imagine a fix point on the railroad : when the first wheel crosses it, you sart counting the time and when the rear one crosses it you stop. So the you have the time (t) it took for the train to travel the distance (d) from the rear wheel to the back wheel.
since rate = distance/time
You have r = 100/2 in the question above
Hope that helps !
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